37x^2-14x-176=0

Solution for 37x^2-14x-176=0 equation:

37x^2-14x-176=0

a = 37; b = -14; c = -176;
Δ = b2-4ac
Δ = -142-4·37·(-176)
Δ = 26244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{26244}=162$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-162}{2*37}=\frac{-148}{74}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+162}{2*37}=\frac{176}{74}
=2+14/37
$